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3x^2+9x-82=0
a = 3; b = 9; c = -82;
Δ = b2-4ac
Δ = 92-4·3·(-82)
Δ = 1065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{1065}}{2*3}=\frac{-9-\sqrt{1065}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{1065}}{2*3}=\frac{-9+\sqrt{1065}}{6} $
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